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		| daj95376 
 
 
 Joined: 23 Aug 2008
 Posts: 3854
 
 
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				|  Posted: Thu Mar 12, 2009 11:53 am    Post subject: Set VH_2 Puzzle 4 |   |  
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				|  	  | Code: |  	  | +-----------------------+ | 3 . . | . . . | . . . |
 | . . . | . 8 . | . . 4 |
 | . . 4 | . . . | . 3 2 |
 |-------+-------+-------|
 | . . . | . 2 . | . 8 . |
 | . 2 . | 8 6 1 | 3 . 9 |
 | . . . | . 4 9 | . . 5 |
 |-------+-------+-------|
 | . . . | . 3 . | 2 . 1 |
 | . . 1 | 2 . . | . . . |
 | . 6 2 | . 1 7 | 5 . . |
 +-----------------------+
 
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 Play this puzzle online at the Daily Sudoku site
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		| storm_norm 
 
 
 Joined: 18 Oct 2007
 Posts: 1741
 
 
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				|  Posted: Mon Mar 16, 2009 7:41 am    Post subject: |   |  
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				| good puzzle UR 1,5
 UR 7,8
 xyz
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Mon Mar 16, 2009 12:49 pm    Post subject: |   |  
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				| I used Norm's URs, plus a Hidden UR on 69 and finished with an XY-Wing on 897. |  |  
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Mon Mar 16, 2009 2:31 pm    Post subject: |   |  
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				| I also did the UR78, UR15 and the xyz-wing and then realized that the UR78 was not required to complete the puzzle. 
 Also, I saw (again what I think is) a 6-cell DP15, but could not do anything with it.
 
 Ted
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Mon Mar 16, 2009 2:35 pm    Post subject: |   |  
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				|  	  | Marty R. wrote: |  	  | I used Norm's URs, plus a Hidden UR on 69 and finished with an XY-Wing on 897. | 
 Marty, I am still hazy about "Hidden URs". Would you please provide some detail about this example? Thanks much.............
 
 Ted
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		| storm_norm 
 
 
 Joined: 18 Oct 2007
 Posts: 1741
 
 
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				|  Posted: Mon Mar 16, 2009 5:55 pm    Post subject: |   |  
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				|  	  | Code: |  	  | .---------------------.---------------------.---------------------. | 3      15    U689   | 4      79     2     |U6789   15     78    |
 | 2      79    U69    | 135    8      35    |U679    15     4     |
 | 17     15789  4     | 15     79     6     | 789    3      2     |
 :---------------------+---------------------+---------------------:
 | 17     179    39    | 357    2      35    | 4      8      6     |
 | 4      2      5     | 8      6      1     | 3      7      9     |
 | 6      78     38    | 37     4      9     | 1      2      5     |
 :---------------------+---------------------+---------------------:
 | 5      4      7     | 6      3      8     | 2      9      1     |
 | 9      3      1     | 2      5      4     | 78     6      78    |
 | 8      6      2     | 9      1      7     | 5      4      3     |
 '---------------------'---------------------'---------------------'
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 Ted,
 this grid represents the state directly after the UR move on 1,5.
 
 then notice how the 6's form a perfect x-wing.
 the candidate 9 also shares those same cells.
 then notice the {6,9} cell in r2c3.
 we know from the rules of how to prevent the deadly pattern that those four cells can't be left with {6,9} in them because then the puzzle would have two solutions.
 
 since the x-wing pattern exists on 6, we know that either
 r2c3 or r1c6 is going to be a 6  or
 r1c3 or r2c6 is going to be a 6
 
 well guess what?  if r1c3 and r2c6 are 6, then that forces 9 into r2c3,
 and that would leave a 9 (and other candidates) in r1c6. ok, moving on
 if 6 were in r2c3, that forces 6 in r1c6
 but there are still 9's in r1c3 and r2c6
 so there still exists the possibility of multiple solutions
 
 we now know the consequences of r2c3 being either a 9 or a 6.
 in either case, the only sure way to avoid the DP is to remove the 9 from r1c6 since we know that 6 is going in two of the 4 cells, we just don't know that at this point.
 
 
  	  | Code: |  	  | 69..................69 69..................69
 
 solution 1
 
 6...................9
 9...................6
 
 
 solution 2
 
 9...................6
 6...................9
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 in a general sense.
 if you see a bi-value cell like the {6,9} cell and one of the candidates form a perfect x-wing, and the other candidate, {9} in this case, shares those same 4 cells.  then it can be eliminated from the opposite corner cell.
 
 anyone have a more efficient way to explain this?
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Mon Mar 16, 2009 6:38 pm    Post subject: |   |  
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				| Norm, that is a great explanation; thanks. I thought that I understood the situation, and I even noticed the possibility in this puzzle but it did not work. As to why it did not work is simple; I missed the naked triple in row2 that deleted the <6> from r2c6 so I did not have a X-wing on <6>. 
 Again, your post clarified Hidden URs for me ....
 
 Ted
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