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Energizer

 
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Thu May 12, 2011 1:46 am    Post subject: Energizer Reply with quote

Keeps on going ...
Code:
Puzzle: BB042911sh
+-------+-------+-------+
| . 3 . | . 4 . | . 2 . |
| 5 . 8 | . 6 . | 7 . 4 |
| . 4 1 | . . . | 3 8 . |
+-------+-------+-------+
| . . . | 8 . 3 | . . . |
| 1 7 . | . . . | . 9 2 |
| . . . | 2 . 7 | . . . |
+-------+-------+-------+
| . 1 4 | . . . | 2 6 . |
| 3 . 7 | . 2 . | 1 . 8 |
| . 5 . | . 8 . | . 3 . |
+-------+-------+-------+
Keith
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu May 12, 2011 4:59 am    Post subject: Reply with quote

Yes, this was a little stubborn.

W-Wing (59), flightless with transport; r3c9<>9
XY-Wing (692); r4c3<>2
Hidden UR (46); r4c1<>6, r6c7<>4
AIC; r9c49<>9
BUG+1
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Thu May 12, 2011 9:30 pm    Post subject: Reply with quote

After basics:
Code:
+----------------+----------------+----------------+
| 7    3    69   | 1    4    8    | 59   2    569  |
| 5    29   8    | 3    6    29d  | 7    1    4    |
| 269  4    1    | 59e  7    259d | 3    8   6-9   |
+----------------+----------------+----------------+
| 246  26   256  | 8    9    3    | 456  7    1    |
| 1    7    3    | 46   5    46   | 8    9    2    |
| 469  8    569  | 2    1    7    | 456  45   3    |
+----------------+----------------+----------------+
| 8    1    4    | 579  3    59c  | 2    6    579b |
| 3    69   7    | 4569 2    46   | 1    45   8    |
| 269  5    269  | 4679 8    1    | 49   3    79a  |
+----------------+----------------+----------------+

Note the triple abc. Any cell that sees all three cannot be 9. If c is 9, so is e, making the elimination shown.

Interesting, though it does not solve the puzzle.

Keith
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu May 12, 2011 11:15 pm    Post subject: Reply with quote

You sat toh-MAY-toh, I say toh-MAH-toh. I see it as an XYZ-Transport. But that elimination is the one I made with the flightless W-Wing on 59, using the same transport.

I had another solution, this one an eight-stepper, but was all pattern-based and didn't need an AIC.
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susume



Joined: 13 May 2011
Posts: 36
Location: Southeastern US

PostPosted: Fri May 13, 2011 4:18 am    Post subject: Reply with quote

Fun puzzle! It seems to me a UR and a chain of 9s also cracks it.

Starting from "after basics" as given by keith,
UR 46 requires either 5 or 9 in r8c4, and r7c6 takes the other; r79c4<>59

I hope I've remembered the right notation for an AIC:

r2c2=9=r2c6-9-r3c4=9=r8c4-9-r8c2=9=r2c2 => (9)r2c2
Singles to end.

I've been away from the forums for a couple of years. Please let me know if I've got the loop or its notation wrong.
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Fri May 13, 2011 6:15 am    Post subject: Reply with quote

two step here.

http://youtu.be/cg7b3fwC88U
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Fri May 13, 2011 11:54 am    Post subject: Reply with quote

FWIW, you can do it in one step if you think of the internal SIS in the UR rather than as a Type 1...
Code:
ur(46)r58c46[(9=5)r8c4] - (5=9)r7c6 - r2c6=r2c2 ; r8c2<>9

.. though clearly it amounts to the same solution.
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