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Could use some help

 
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shoeless



Joined: 03 Aug 2007
Posts: 13

PostPosted: Fri Nov 08, 2019 6:35 pm    Post subject: Could use some help Reply with quote

Anybody see a good next step in this one?

Code:

+---------------+----------------+-----------------+
| 29   5    17  | 8    4   279   | 3   6     127   |
| 234  8    347 | 1    6   237   | 47  9     5     |
| 2349 1379 6   | 237  79  5     | 147 8     1247  |
+---------------+----------------+-----------------+
| 8    6    2   | 5    3   147   | 147 147   9     |
| 49   79   5   | 6    179 8     | 2   1347  1347  |
| 1    379  347 | 47   2   479   | 8   5     6     |
+---------------+----------------+-----------------+
| 5    2    13  | 9    178 1347  | 6   1347  13478 |
| 7    4    9   | 23   18  6     | 5   123   138   |
| 6    13   8   | 2347 5   12347 | 9   12347 1347  |
+---------------+----------------+-----------------+

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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 933
Location: Rimini, Italy

PostPosted: Fri Nov 08, 2019 7:52 pm    Post subject: Reply with quote

Hi shoeless,

L.C. with number 3 in r23c1 and -3 in r2c3,r3c2
Naked Pairs 4,7 in r2c37
then
A.I.C. in r5c1,
if r5c1=9 then r1c6=9 and no number 9 in r6, so r5c1=4.

Ciao Gianni
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shoeless



Joined: 03 Aug 2007
Posts: 13

PostPosted: Tue Nov 12, 2019 9:04 pm    Post subject: Reply with quote

Thanks, that helped me get a bit further to here. I'm thinking I should just move on to another puzzle. Laughing

Code:

+------------+----------------+----------------+
| 29  5   17 | 8    4   279   | 3  6     12    |
| 23  8   4  | 1    6   23    | 7  9     5     |
| 239 17  6  | 237  79  5     | 14 8     124   |
+------------+----------------+----------------+
| 8   6   2  | 5    3   17    | 14 147   9     |
| 4   79  5  | 6    179 8     | 2  137   137   |
| 1   379 37 | 47   2   479   | 8  5     6     |
+------------+----------------+----------------+
| 5   2   13 | 9    178 1347  | 6  1347  13478 |
| 7   4   9  | 23   18  6     | 5  123   138   |
| 6   13  8  | 2347 5   12347 | 9  12347 1347  |
+------------+----------------+----------------+

Play this puzzle online at the Daily Sudoku site
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 933
Location: Rimini, Italy

PostPosted: Tue Nov 12, 2019 9:48 pm    Post subject: Reply with quote

Hi shoeless,

A.I.C. in r3c5,
if r3c5=7 then r5c5=9 r4c6=1 r4c7=4 r3c7=1 r3c2=7 and too many 7 in row 3
so r3c5=9

Ciao Gianni
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shoeless



Joined: 03 Aug 2007
Posts: 13

PostPosted: Wed Nov 13, 2019 5:42 pm    Post subject: Reply with quote

ZeroAssoluto wrote:
Hi shoeless,

A.I.C. in r3c5,
if r3c5=7 then r5c5=9 r4c6=1 r4c7=4 r3c7=1 r3c2=7 and too many 7 in row 3
so r3c5=9

Ciao Gianni


Thanks, that broke it free alright. Out of curiosity, how did you see that? Is there some sort of dependency pattern that you recognized?

Thanks again.
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 933
Location: Rimini, Italy

PostPosted: Wed Nov 13, 2019 7:55 pm    Post subject: Reply with quote

No, no one pattern.
It's routine or experience or ...
The number 9 is present only twice in the sector, row and column and I look at it for a color or other possibilities.
Sometimes it helps other times not.
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WorldO



Joined: 04 May 2016
Posts: 5

PostPosted: Mon Jun 22, 2020 9:11 am    Post subject: Reply with quote

I see now why I missed the Sue de Coq. It was no longer available due to the Naked Triple , which essentially made the same eliminations. Still a nice technique. I needed something similar to Clement's last two steps to solve as well.
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