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VH+ 012822

 
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immpy



Joined: 06 May 2017
Posts: 570

PostPosted: Fri Jan 28, 2022 6:21 pm    Post subject: VH+ 012822 Reply with quote

Hello all, enjoy the puzzle.

Code:

+-------+-------+-------+
| . 5 . | . . . | . 2 . |
| 6 2 . | . 4 . | . 1 5 |
| . . . | 7 5 2 | . . . |
+-------+-------+-------+
| . . 7 | . 3 . | 9 . . |
| . . 2 | 5 9 1 | 4 . . |
| . . 1 | . 8 . | 5 . . |
+-------+-------+-------+
| . . . | 1 6 3 | . . . |
| 2 3 . | . . . | . 5 6 |
| . 1 . | . . . | . 4 . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp
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TomC



Joined: 30 Oct 2020
Posts: 349
Location: Wales

PostPosted: Fri Jan 28, 2022 8:23 pm    Post subject: Reply with quote

Code:

+------------+-----------+----------+
| 7  5  349  | 369 1 69  | 8 2  349 |
| 6  2  39   | 389 4 89  | 7 1  5   |
| 1  89 3489 | 7   5 2   | 6 39 349 |
+------------+-----------+----------+
| 5  48 7    | 2   3 46  | 9 68 1   |
| 38 6  2    | 5   9 1   | 4 7  38  |
| 39 49 1    | 46  8 7   | 5 36 2   |
+------------+-----------+----------+
| 4  7  5    | 1   6 3   | 2 89 89  |
| 2  3  89   | 489 7 489 | 1 5  6   |
| 89 1  6    | 89  2 5   | 3 4  7   |
+------------+-----------+----------+

Play this puzzle online at the Daily Sudoku site

At this point
If r4c8=6
then stay in c8 gives r3c8 = 9
also stay in r4 gives r3c2 = 9
so we can safely say r4c8 <>6
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sun Jan 30, 2022 11:48 am    Post subject: Reply with quote

I jumped onto the same chain but at a different point. If you make r3c2 = 9 you get two 9’s in col 2. Or if you complete the loop the starting 9 in r3c2 is evicted by the loop. R3c2 < > 9
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sun Jan 30, 2022 11:57 am    Post subject: Reply with quote

Staying on the cell at r3c2. Whatever value <89> it takes, r4c8 < > 6.

Last edited by Mogulmeister on Sun Jan 30, 2022 12:58 pm; edited 1 time in total
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sun Jan 30, 2022 12:13 pm    Post subject: Reply with quote

Sticking with r3c2 there are pincers for 8 on r3c2 and r4c8 removing 8 from r4c2
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immpy



Joined: 06 May 2017
Posts: 570

PostPosted: Sun Jan 30, 2022 5:17 pm    Post subject: Reply with quote

I used a W-Wing: 9/8 in r3c2,r7c8 connected by 8 in r4c28=>r3c8<>9

cheers...immp
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sun Jan 30, 2022 7:15 pm    Post subject: Reply with quote

Very nice Immp! That r3c2 is a cornerstone on this puzzle!
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Clement



Joined: 24 Apr 2006
Posts: 1110
Location: Dar es Salaam Tanzania

PostPosted: Mon Jan 31, 2022 7:35 pm    Post subject: VH + 012822 Reply with quote

Code:

+------------------+-----------------+----------------+
| 7     5     349  | 369    1    69  | 8    2     349 |
| 6     2     39   | 389    4    89  | 7    1     5   |
| 1    c89    3489 | 7      5    2   | 6   d39    349 |
+------------------+-----------------+----------------+
| 5     48    7    | 2      3    46  | 9    68    1   |
| 38    6     2    | 5      9    1   | 4    7     38  |
|a39   b49    1    | 46     8    7   | 5    6-3   2   |
+------------------+-----------------+----------------+
| 4     7     5    | 1      6    3   | 2    89    89  |
| 2     3     89   | 489    7    489 | 1    5     6   |
| 89    1     6    | 89     2    5   | 3    4     7   |
+------------------+-----------------+----------------+

(3=9)r1c6 - r6c2 = r3c2 - (9=3)r3c8 => - 3r6c8; stte
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Mon Jan 31, 2022 8:04 pm    Post subject: Reply with quote

Very nice indeed Clement. Good to see you. I think you have a typo first step is r6c1 ?
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TomC



Joined: 30 Oct 2020
Posts: 349
Location: Wales

PostPosted: Mon Jan 31, 2022 8:27 pm    Post subject: Reply with quote

Another way
if r5c1=3, r6c8=3, r3c8=9, r3c2=8
where does the <8> go in box 4?
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Tue Feb 01, 2022 6:45 am    Post subject: Reply with quote

…or extend Clement’s chain by one step so that there are pincers for 3 at (a) and r5c9.
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Tue Feb 01, 2022 4:11 pm    Post subject: Reply with quote

A slightly odd pincer movement:

(9=6)r1c6-(6=4)r4c6-(4=6)r6c4-(6=3)r6c8-(3=9)r3c8 so r1c9 < > 9

Pincers for 9 at r1c6 and r3c8.
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Clement



Joined: 24 Apr 2006
Posts: 1110
Location: Dar es Salaam Tanzania

PostPosted: Tue Feb 01, 2022 4:37 pm    Post subject: Reply with quote

Mogulmeister wrote:
Very nice indeed Clement. Good to see you. I think you have a typo first step is r6c1 ?
Yes you are quite right it was a typo. I was on another forum I am now back.
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Tue Feb 01, 2022 4:40 pm    Post subject: Reply with quote

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TomC



Joined: 30 Oct 2020
Posts: 349
Location: Wales

PostPosted: Tue Feb 01, 2022 8:04 pm    Post subject: Reply with quote

There is also an XY chain starting at r8c4, if that is 4 then 4-6-3-9-8-4-6-4 puts 4 in r6c4 as well
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Wed Feb 02, 2022 9:41 am    Post subject: Reply with quote

This is where Eureka can be helpful but I think I understand - you use the 4 in r8c4 to jump onto an xy chain that reverses round Clement's chain but instead of going c to b adds two extra steps going from c via r4c26 to plonk a contradictory 4 in r6c4 ? Two fours in col 4 and r8c4 < > 4 and by implication r6c4 = 4 (< > 6).

Very good.

Strictly speaking - (but who cares really ?) - the xy chain proper starts at r6c4 because the 4 at r8c4 is part of an xyz <489> cell which is the "nudge". Which you don't actually need.

You could use exactly the same chain and start (4=6)r6c4 ("r6c4 not 4 must be 6')
and follow it round to the contradiction (6=4)r6c4 ("r6c4 not 6 must be 4")

So r6c4 = 4 (< > 6).
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