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		| peter newman 
 
 
 Joined: 29 May 2006
 Posts: 3
 
 
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				|  Posted: Wed Jun 14, 2006 5:53 pm    Post subject: next number |   |  
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				| can anybody give me the next number and why 
 7x53x96x2
 3xx5xx79x
 4x9x8x351
 x4x1xx5x7
 853674129
 1x7x5xxxx
 231x6x9x5
 xx8x35x1x
 5x4xx1xx3
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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Wed Jun 14, 2006 9:18 pm    Post subject: Some progress |   |  
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				| Here is the position you posted, after clearing hidden pairs, etc: 
 
  	  | Code: |  	  | +----------------+----------------+----------------+
 | 7    18   5    | 3    14   9    | 6    48   2    |
 | 3    18   26   | 5    14   26   | 7    9    48   |
 | 4    26   9    | 27   8    267  | 3    5    1    |
 +----------------+----------------+----------------+
 | 69   4    26   | 1    29   38   | 5    38   7    |
 | 8    5    3    | 6    7    4    | 1    2    9    |
 | 1    29   7    | 289  5    238  | 48   3468 468  |
 +----------------+----------------+----------------+
 | 2    3    1    | 478  6    78   | 9    478  5    |
 | 69   679  8    | 2479 3    5    | 24   1    46   |
 | 5    679  4    | 2789 29   1    | 28   678  3    |
 +----------------+----------------+----------------+
 
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 There is a Unique Rectangle in R46C68.  You can eliminate <8> from R6C68.
 
 There are strong links on <9> in C15.  You can eliminate <9> from R9C2 and R8C4.  (Either R8C1 or R9C5 is <9>.)
 
 Then, there is an XY-wing on <267> which removes <7> from R9C4.
 
 Then, it seems, you have to look for chains.
 
 Keith
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		| TKiel 
 
 
 Joined: 22 Feb 2006
 Posts: 292
 Location: Kalamazoo, MI
 
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				|  Posted: Thu Jun 15, 2006 12:01 am    Post subject: |   |  
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				| From Keith's grid, colouring on digit 2 excludes 2 from r6c6, which creates a naked pair that allows a placement in r6c7.  After that it's all singles. |  |  
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Thu Jun 15, 2006 4:03 am    Post subject: |   |  
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				|  	  | Quote: |  	  | Then, there is an XY-wing on <267> which removes <7> from R9C4. | 
 
 Keith, I'm missing something here, unless 679 counts as a 67. ??
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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Thu Jun 15, 2006 10:36 am    Post subject: |   |  
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				| The <9> in R9C2 is eliminated in the previous step (coloring on the <9>'s). 
 Keith
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Thu Jun 15, 2006 3:41 pm    Post subject: |   |  
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				|  	  | keith wrote: |  	  | The <9> in R9C2 is eliminated in the previous step (coloring on the <9>'s). 
 Keith
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 Oops, sorry, I missed that. Thanks.
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		| peter newman 
 
 
 Joined: 29 May 2006
 Posts: 3
 
 
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				|  Posted: Thu Jun 15, 2006 6:08 pm    Post subject: |   |  
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				|  	  | TKiel wrote: |  	  | From Keith's grid, colouring on digit 2 excludes 2 from r6c6, which creates a naked pair that allows a placement in r6c7.  After that it's all singles. | 
 
 So is this the solution, if so please explain colouring i.e. why 2's excluded.
 
 Pete.
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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Thu Jun 15, 2006 9:09 pm    Post subject: Coloring |   |  
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				| Starting from here (the same as above, but I have labeled some cells): 
  	  | Code: |  	  | +----------------+----------------+----------------+
 | 7    18   5    | 3    14   9    | 6    48   2    |
 | 3    18   26b  | 5    14   26a  | 7    9    48   |
 | 4    26a  9    | 27   8    267  | 3    5    1    |
 +----------------+----------------+----------------+
 | 69   4    26   | 1    29   38   | 5    38   7    |
 | 8    5    3    | 6    7    4    | 1    2    9    |
 | 1    29b  7    | 289  5    238c | 48   3468 468  |
 +----------------+----------------+----------------+
 | 2    3    1    | 478  6    78   | 9    478  5    |
 | 69   679  8    | 2479 3    5    | 24   1    46   |
 | 5    679  4    | 2789 29   1    | 28   678  3    |
 +----------------+----------------+----------------+
 
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 a and b label conjugate pairs (or strong links) in R2, B1, and C2.  In each of these there are only two candidates for <2>.  Notice how these links form a chain from R1C6 to R6C2.  In the solution, either all the cells labeled a are <2>, OR all the cells labeled b are <2>.
 
 So, the cell labeled c, R6C6, cannot be <2>.
 
 Nice observation, Tracy!
 
 Keith
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