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		| sarah Guest
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 4:15 am    Post subject: March 8!!! |   |  
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				| Very strange ... I often solve very hard puzzles, yet this "hard" puzzle has me so stumped I can't get more than 3 numbers filled in!!!  I'm totally puzzled (no pun intended).   
 So far I have 8 in c1r5, 5 in c9r4 and 9 in c3r8.  Draw gives a hint of 8 in c7r9, then 2 in c9r9.  Those hints not only leave me clueless still, but I can't figure out why they make sense.
 
 Any help?
 
 Thanks!
 Sarah
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		| guest Guest
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 9:54 am    Post subject: Re: March 8!!! |   |  
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				|  	  | sarah wrote: |  	  | ... 5 in c9r4 ... | 
 I dont know how you found this.
 Anyway, the key is the naked triplet in box3/column 8.
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		| George woods Guest
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 11:58 am    Post subject: solving it |   |  
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				| e7b7e98i3h3f4 is how I started 
 abc
 def
 ghi
 
 and e7 menas put a 7 into obvious square in block e
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		| Guest 
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 12:04 pm    Post subject: |   |  
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				| George, i suppose you have another puzzle, i was talking about this one (where 7 is a given in block e)
 
  	  | Code: |  	  | ------------ .8.|1..|4..
 1.7|...|..9
 ...|..6|1.3
 ------------
 7..|..4|.6.
 ...|2.3|...
 .9.|7..|..8
 ------------
 2.8|5..|...
 5..|...|7.1
 ..3|..9|.5.
 ------------
 
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		| george woods Guest
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 12:10 pm    Post subject: |   |  
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				| Ok I haven't checked it against original but my record is 
 f7d8i8g9i2f5c65
 
 I have put an exclamation mark beside f7 implying something subtle!
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		| george woods Guest
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 12:24 pm    Post subject: march 8 |   |  
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				| The subtelty arises from the pair 56 in Cc and Cg (because of the 5 and 6 in col 8 |  | 
	
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		| george Guest
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 12:27 pm    Post subject: |   |  
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				| I mean of course Cc and Cd |  | 
	
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		| Guest 
 
 
 
 
 
 
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				|  Posted: Tue Mar 28, 2006 1:38 pm    Post subject: |   |  
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				| Yep, now we are on the same line. The hidden pair 56 in box 3 (c) is the counterpart to the triplet i mentioned. |  | 
	
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		| TKiel 
 
 
 Joined: 22 Feb 2006
 Posts: 292
 Location: Kalamazoo, MI
 
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				|  Posted: Tue Mar 28, 2006 9:11 pm    Post subject: |   |  
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				| Sarah, 
 If you've made the exclusions from the naked triple in box 3, then the only possibility in box 9 for an 8 is r9c7, which then makes r9c9 the only possibility for a 2.
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		| sarah Guest
 
 
 
 
 
 
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				|  Posted: Thu Mar 30, 2006 7:20 pm    Post subject: |   |  
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				| Tracy- Thank you.  Your response was the only one that made any sense to me.  I do not know what a "naked triplet" is... although I do have the limitations of 27 for c8r1, 28 for c8r2, and 278 for c8r3.  So I see how the 8 must therefore be in c7r9.  But c9r9 can still be a 2 OR a 4, no? 
 And what is George going on about?  All his letters and numbers are a mystery to me...
 
 Sarah
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		| sarah Guest
 
 
 
 
 
 
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				|  Posted: Thu Mar 30, 2006 7:27 pm    Post subject: |   |  
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				| I take that back -- I see why c9r9 has to be a 2! Thank you.
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		| Guest 
 
 
 
 
 
 
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				|  Posted: Fri Mar 31, 2006 5:17 pm    Post subject: |   |  
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				| Glad to see a response finally, Sarah, sorry for the "t" in "naked triplet" (i am not English), which seemed to confuse you so, that - you could not see the triple in the 3 cells i mentioned
 - not the naked pair i mentioned
 - and you were not able to ask what i meant with it
 i will .ry .o avoid .he "t" in the fu.ure
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