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Butterfly Pattern VH+

 
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immpy



Joined: 06 May 2017
Posts: 504

PostPosted: Thu Jun 16, 2022 8:26 pm    Post subject: Butterfly Pattern VH+ Reply with quote

Hello all, enjoy the puzzle.

Code:

+-------+-------+-------+
| . . . | . . . | . . . |
| . . . | 9 8 3 | . . . |
| 9 5 . | 2 7 6 | . 1 3 |
+-------+-------+-------+
| . 4 . | . . . | . 8 . |
| . 6 8 | 1 . 7 | 4 5 . |
| . . 5 | . . . | 6 . . |
+-------+-------+-------+
| . . . | 3 . 5 | . . . |
| . 1 . | . . . | . 7 . |
| . 9 . | . 4 . | . 2 . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp
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Clement



Joined: 24 Apr 2006
Posts: 1089
Location: Dar es Salaam Tanzania

PostPosted: Fri Jun 17, 2022 10:35 am    Post subject: Butterfiy Pattern VH+ Reply with quote

Code:

+------------------+-----------------+--------------------+
| 8      3    a67  | 45    15     14 | 2      9      6-7  |
| 67     2     1   | 9     8      3  | 57     46     4567 |
| 9      5     4   | 2     7      6  | 8      1      3    |
+------------------+-----------------+--------------------+
| 3      4     9   | 56    56     2  | 17     8     e17   |
| 2      6     8   | 1     3      7  | 4      5      9    |
| 1      7     5   | 48    9      48 | 6      3      2    |
+------------------+-----------------+--------------------+
| 467    8    b267 | 3    c126    5  | 9      46    d146  |
| 456    1     236 | 68    26     9  | 35     7      4568 |
| 56     9     36  | 7     4      18 | 135    2      1568 |
+------------------+-----------------+--------------------+

(7)r1c3 = (7-2)r7c3 = (2-1)r7c5 = r7c9 - (1=7)r4c9 => - 7r1c9; stte
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TomC



Joined: 30 Oct 2020
Posts: 249
Location: Wales

PostPosted: Fri Jun 17, 2022 11:08 am    Post subject: Reply with quote

Similar solution to Clement, a=6 to solve
Code:

+----------------+---------------+------------------+
|  8     3   67  | 45   15    14 | 2     9    b67   |
| a67    2   1   | 9    8     3  | 57    46    4567 |
|  9     5   4   | 2    7     6  | 8     1     3    |
+----------------+---------------+------------------+
|  3     4   9   | 56   56    2  | 17    8    c17   |
|  2     6   8   | 1    3     7  | 4     5     9    |
|  1     7   5   | 48   9     48 | 6     3     2    |
+----------------+---------------+------------------+
| x467   8   267 | 3    126   5  | 9    x46   x146  |
|  456   1   236 | 68   26    9  | 35    7     4568 |
|  56    9   36  | 7    4     18 | 135   2     1568 |
+----------------+---------------+------------------+

Play this puzzle online at the Daily Sudoku site

If a=7, b=7, c=1 leads to <46> "triple" in r7c189
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Clement



Joined: 24 Apr 2006
Posts: 1089
Location: Dar es Salaam Tanzania

PostPosted: Fri Jun 17, 2022 11:52 am    Post subject: Reply with quote

TomC wrote:
Similar solution to Clement, a=6 to solve
Code:

+----------------+---------------+------------------+
|  8     3   67  | 45   15    14 | 2     9    b67   |
| a67    2   1   | 9    8     3  | 57    46    4567 |
|  9     5   4   | 2    7     6  | 8     1     3    |
+----------------+---------------+------------------+
|  3     4   9   | 56   56    2  | 17    8    c17   |
|  2     6   8   | 1    3     7  | 4     5     9    |
|  1     7   5   | 48   9     48 | 6     3     2    |
+----------------+---------------+------------------+
| x467   8   267 | 3    126   5  | 9    x46   x146  |
|  456   1   236 | 68   26    9  | 35    7     4568 |
|  56    9   36  | 7    4     18 | 135   2     1568 |
+----------------+---------------+------------------+

Play this puzzle online at the Daily Sudoku site

If a=7, b=7, c=1 leads to <46> "triple" in r7c189
I think c=(1)r4c9 leads to pair( 4|6)r7c89 which sets r7c1 to 7 which can be written as a chain in Eureka Notation as:
7r2c1 - r2c79 = r1c9 - (7=1)r4c9 - (1=4|6)r7c89 - (4|6=7)r7c1 - (7=6)r2c1 => - 7r2c1; stte
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TomC



Joined: 30 Oct 2020
Posts: 249
Location: Wales

PostPosted: Fri Jun 17, 2022 12:14 pm    Post subject: Reply with quote

Thanks for the notation Clement, I didn't think you needed a chain when three <46> pairs appear in one row

I probably should have explained it---- If a=7, x=<46>, b=7, c=1, x=<46>
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dongrave



Joined: 06 Mar 2014
Posts: 487

PostPosted: Fri Jun 17, 2022 7:50 pm    Post subject: Reply with quote

Very interesting! And I noticed that if you take Clement's contradictory chain and apply the typical trick (which I learned from him and Marty) of beginning the chain one cell over, you'll end up with a forcing chain with pincers on both ends.

In this case it would be:
7r2c79 = r1c9 - (7=1)r4c9 - (1=4|6)r7c89 - (4|6=7)r7c1 => r2c1 <> 7; stte.
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