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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Tue Oct 19, 2010 4:07 am Post subject: Puzzle 10/10/19: C XY |
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| Code: | +-----------------------+
| 6 . . | . 1 4 | . . . |
| . 5 8 | 3 . . | . . . |
| . 1 . | . 6 7 | 5 . . |
|-------+-------+-------|
| . 4 . | . 7 . | 8 5 1 |
| 8 . 1 | 9 3 . | . . 2 |
| 5 . 2 | . . . | 6 9 . |
|-------+-------+-------|
| . . 5 | 7 . 9 | 1 . . |
| . . . | 4 . 1 | . . . |
| . . . | 6 5 . | . . . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Tue Oct 19, 2010 5:44 pm Post subject: |
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Two steps...
| Quote: | kite(4) r7, c3 ; r3c9<>4
m-wing-like with 3-cell-xy SL(79) instead of bivalue ; (7=4)r2c1-(4=3)r3c3-(3=9)r4c3 - r4c1=(9-7)r8c1=r9c3 ; r1c3<>7 |
With hindsight, the last move can be played after basics with a one-step '"almost" play that essentially combines the contradiction in 4s | Code: | | fin (9)r3c3 - (9=4)r3c9 - r79c9=r9c8 - r9c3=r7c1 - (4=7)r2c1 |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed Oct 20, 2010 4:38 am Post subject: |
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Four moves here.
Multi-coloring (4)
X-Wing (7)
XYZ-Wing (238)
XY-Chain, r4c1<>9 |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Wed Oct 20, 2010 2:09 pm Post subject: |
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This puzzle offered a variety of non-productive steps; I was headed for a BBDB solution. On restarting, I found a two stepper............
skyscraper 4 r27c1; r3c9<>4
AW-wing (34)r3c3|r7c1 SL (3)r4c13 with fin (2)r7c1; r2c1<>4
If w-wing is true, r2c1<>4
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If fin is true: (2)r7c1-(2=34)als:r3c13-(4)r2c1
Ted |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Wed Oct 20, 2010 2:58 pm Post subject: |
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My solver used 3x steps to reduce this puzzle to something "cooperative". Otherwise, although the following is interesting, I never managed anything "prettier" than a cumbersome discontinuous network.
| Code: | after basics -- overlapping constraints
+--------------------------------------------------------------+
| 6 239 379 | 5 1 4 | 239 2378 789 |
| 47 5 8 | 3 9 2 | 47 1 6 |
| 39+24 1 39+4 | 8 6 7 | 5 234 49 |
|--------------------+--------------------+--------------------|
| 39 4 39 | 2 7 6 | 8 5 1 |
| 8 6 1 | 9 3 5 | 47 47 2 |
| 5 7 2 | 1 4 8 | 6 9 3 |
|--------------------+--------------------+--------------------|
| 234 238 5 | 7 28 9 | 1 6 48 |
| 279 289 6 | 4 28 1 | 239 2378 5 |
| 1 289 479 | 6 5 3 | 29 2478 4789 |
+--------------------------------------------------------------+
# 52 eliminations remain
UR[(4)r3c13 = (2)r3c1] -and-
SL[(4)r3c13 = (4)r2c1]
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| Code: | (4)r2c1-UR[(4)r3c13=(2)r3c1]-(24=3)r7c1-r4c1=r4c3-(34=9)r3c3-(9=4)r3c9-r8c9=r7c1-(4)r2c1
\ / /
-----------------------------------------
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Yes, I know that I commited a network "sin" by assigning two different values to r7c1, but I didn't want to stop the chain after (=4)r3c9 eliminated the last <4> in [r7]. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed Oct 20, 2010 3:56 pm Post subject: |
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| Quote: | | This puzzle offered a variety of non-productive steps |
I'm offering up my assistance to anyone who asks, as this is my area of expertise.  |
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