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Puzzle 11/01/20 BBDB

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Thu Jan 20, 2011 4:57 am    Post subject: Puzzle 11/01/20 BBDB Reply with quote
Code:
 +-----------------------+
 | 6 . . | 4 2 . | 9 . 7 |
 | . 2 . | 9 7 . | . . . |
 | . . 4 | . 3 . | . 6 . |
 |-------+-------+-------|
 | 5 9 . | 2 6 4 | . . . |
 | 7 8 6 | 5 . 9 | . . 4 |
 | . . . | 3 8 . | . . 6 |
 |-------+-------+-------|
 | 8 . . | . . . | 2 . . |
 | . . 2 | . . . | . . 9 |
 | 4 . . | . 9 2 | . 8 3 |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Thu Jan 20, 2011 4:44 pm    Post subject: Reply with quote
Four steps for me.

Quote:
XYZ-Wing (158)
X-Wing (1)
UR (45) with pseudo cell 17
W-Wing (67)
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JC Van Hay



Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
PostPosted: Thu Jan 20, 2011 6:59 pm    Post subject: Reply with quote
One "simple"(!?) step proof ...
Quote:
From XY Ring in R39C47 : Either r3c4=1, NT(167)r379c4, r8c4=8, NP(13)r8c16, r8c2=6; Or r3c4=8, r3c7=1, r9c7=6 => r8c7<>6.

In Eureka notation : (6=1)r9c7-1r3c7=(167)r379c4-(167=8)r8c4-(8=136)r8c126 : 6r9c7=6r8c2 => -6r8c7.

8-SIS AIC : (61)R9C7 1R3 (1=67)R79C4 (167=8)R8C4 (8=13)R8C16 (13=6)R8C2 : 6r9c7=6r8c2 => -6r8c7.
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK
PostPosted: Thu Jan 20, 2011 11:53 pm    Post subject: Reply with quote
Another approach to make JC's elimination...
Code:
Kraken aahs (47)r8c78, (4)r8c5, (7)r8c4 ; r8c7<>6
hp(47)
||
(4)r8c5 - (4=5)r7c5 - (5=1)r7c9 - (1=6)r9c7
||
(7)r8c4 - anp(7=16)r79c4 - (1)r4c4=r4c7 - (1=6)r9c7
... but I actually played same moves as Marty's in a different order...
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