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Aug 02 VH

 
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Clement



Joined: 24 Apr 2006
Posts: 1028
Location: Dar es Salaam Tanzania

PostPosted: Sat Aug 01, 2020 9:57 pm    Post subject: Aug 02 VH Reply with quote

Code:

+------------------+---------------------+-------------------+
| 2      1       3 | 7        6        4 | 9       5       8 |
| 9      8       7 | 1        5        3 | 6       2       4 |
| 5      6       4 | 8        2        9 | 7       1       3 |
+------------------+---------------------+-------------------+
| 1      5       9 | 34       8        2 | 34      6       7 |
| 7      34      2 | 5        34       6 | 8       9       1 |
| 8      34      6 | 9        1        7 | 2       34      5 |
+------------------+---------------------+-------------------+
| 6      27      1 | 234*     37-4     5 |(34)     8       9 |
| 4      9       5 | 6        37       8 | 1       37      2 |
| 3      27      8 |(24)      9        1 | 5       47      6 |
+------------------+---------------------+-------------------+

XYZ-Wing 234-4 with apex in r7c4; r7c5 <> 4; stte
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dongrave



Joined: 06 Mar 2014
Posts: 380

PostPosted: Sun Aug 02, 2020 9:44 am    Post subject: Reply with quote

There's also a 347 XYZ Wing with pivot at r7c5 (-3r7c4) that solves it. (The 3 X Wing in rows 4 and 7 does not.)
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Earl



Joined: 30 May 2007
Posts: 635
Location: Victoria, KS

PostPosted: Sun Aug 02, 2020 11:59 am    Post subject: Aug2 VH Reply with quote

UR34 in R4C4,R6C8 by 4s in R9, -3R4C7

Early Earl
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dongrave



Joined: 06 Mar 2014
Posts: 380

PostPosted: Mon Aug 03, 2020 2:03 pm    Post subject: Reply with quote

Hi Earl, I don't completely understand your solution. Is it saying the same thing as something like (3=4)r6c8-r9c8=r9c4-(4=3)r4c4 => r4c7<>3. Thanks, Don.
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immpy



Joined: 06 May 2017
Posts: 344

PostPosted: Mon Aug 03, 2020 4:43 pm    Post subject: Reply with quote

There is an identified UR (or Uniqueness Test type 1) (34) r47c47; but it occurs in four boxes (b5689) instead of the more standard two-box occurrence. Standard application of the technique would be that r7c4<>3,4(=2!); but that is not the case here. I have seen multiple occurrences of this 4-box UR, and in every case the extra candidate (in this case 2) can be eliminated from r7c4. This solves the puzzle easily, albeit without proper logic, as I have been told. Either of the XYZ-Wings work just as well and fit logical parameters.

cheers...immp
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dongrave



Joined: 06 Mar 2014
Posts: 380

PostPosted: Mon Aug 03, 2020 6:00 pm    Post subject: Reply with quote

Thanks for the input immp!

I was confused by Earl's post because I know that the standard UR type 1 has to have the 3,4 pairs in exactly two boxes but as you mentioned this one has them in four (so it's not a 'standard' UR type 1). But then I noticed that he included the phrase 'by 4's in r9' so I was wondering if this was somehow a 'transported' or 'enhanced' UR of some sort because he did not come to the typical UR conclusion that you mentioned (i.e. r7c4 <> 3,4=2).

Thanks, Don.
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immpy



Joined: 06 May 2017
Posts: 344

PostPosted: Tue Aug 04, 2020 4:53 pm    Post subject: Reply with quote

You're welcome dongrave.

Yes, I'm a bit confused by it as well. The only way I can see to make use of the 4's in row 9 is to identify the Skyscraper with the 4's in row 4; and thus r6c8<>4(=3!) and r7c7<>4(=3!). This would solve as well.

cheers...immp
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